Adding the end of the mediums challenges

Python/Medium_Challenges/mayan_calculations.py

@@ -0,0 +1,81 @@
+import sys
+
+#Function to split a string into a list of n char strings
+def split(string, size):
+    i=0
+    liste=[]
+    while(i<len(string)):
+        liste.append(string[i:i+size])
+        i+=size
+    return(liste)
+
+patterns = {0: [], 1: [], 2: [], 3: [], 4: [], 5: [], 6: [], 7: [], 8: [], 9: [], 10: [], 11: [],
+    12: [], 13: [], 14: [], 15: [], 16: [], 17: [], 18: [], 19: []}
+
+num_1line, num_2line = [], []
+separator = "\n"
+
+l, h = [int(i) for i in input().split()]
+splitted = []
+for i in range(h):
+    numeral = input()
+    splitted.append(split(numeral, l))
+print(f"splitted {splitted}", file=sys.stderr, flush = True)
+
+# Adding numbers patterns
+for i in range(h):
+    for j in range (20):
+        patterns[j].append(splitted[i][j])
+print(patterns, file= sys.stderr, flush=True)
+
+# Getting all the line of the first number
+s1 = int(input())
+for i in range(s1):
+    num_1line.append(input())
+
+# Getting all the line of the second number
+s2 = int(input())
+for i in range(s2):
+    num_2line.append(input())
+
+operation = input()
+
+n1, n2 = 0, 0
+
+while (len(num_1line) != 0 or len(num_2line) != 0):
+    for i in range (20):
+        if separator.join(num_1line[:h]) == separator.join(patterns[i]):
+            n1 += i * 20**(len(num_1line) // h -1)
+            num_1line = num_1line[h:]
+
+        if separator.join(num_2line[:h]) == separator.join(patterns[i]):
+            n2 += i * 20**(len(num_2line) // h -1)
+            num_2line = num_2line[h:]
+
+    print(f"{n1} {operation} {n2}", file=sys.stderr, flush=True)
+
+result = 0
+if operation == "+":
+    result = n1 + n2
+elif operation == "-":
+    result = n1 - n2
+elif operation == "*":
+    result = n1 * n2    
+elif operation == "/":
+    result = n1 / n2
+
+#Identify the maximum power we need
+power = 0
+while (20**power < result):
+    power+= 1
+
+# Loop printing the numbers we need
+for i in range(1,power):
+    quotient = result // (20**(power-i))
+    print(f"Debug: resultat {result}, puissance {20**(power-1)}, quotient {quotient}", file=sys.stderr, flush = True)
+    print(separator.join(patterns[quotient]))
+    result -= 20**(power-i) * quotient
+    print(f"Debug: reste {result}", file=sys.stderr, flush=True)
+
+# Printing the rest under 20^1
+print(separator.join(patterns[result]))

Python/Medium_Challenges/scrabble.py

@@ -0,0 +1,34 @@
+from collections import defaultdict
+
+dict = {'a': 1, 'b': 3, 'c': 3, 'd': 2, 'e': 1, 'f': 4, 'g': 2, 'h': 4, 'i': 1, 'j': 8, 'k': 5, 'l': 1, 'm': 3, 'n': 1, 
+'o': 1, 'p': 3, 'q': 10, 'r': 1, 's': 1, 't': 1, 'u': 1, 'v': 4, 'w': 4, 'x': 8, 'y': 4, 'z': 10}
+
+n = int(input())
+words = [input() for _ in range(n)]
+letters = input()
+
+#Function to check if a word is in the scrabble letters
+def solve(s, t):
+    freq = {'a':0, 'b':0, 'c':0, 'd':0, 'e':0, 'f':0, 'g':0, 'h':0, 'i':0, 'j':0, 'k':0, 'l':0, 'm':0, 'n':0, 'o':0,
+    'p':0, 'q':0, 'r':0, 's':0, 't':0, 'u':0, 'v':0, 'w':0, 'x':0, 'y':0, 'z':0}
+    for i in range(len(s)):
+        freq[s[i]] += 1
+
+    for i in range(len(t)):
+        if freq[t[i]] == 0:
+            return False
+        freq[t[i]] -= 1
+    return True
+
+# Compare words with the given letters
+max = 0
+word = ""
+for i in range(n):
+    value = 0
+    if (solve(letters, words[i]) == True):
+        for j in range(len(words[i])):
+            value += dict[words[i][j]]
+        if value > max:
+            max = value
+            word = words[i]
+print(word)

README.md

@@ -41,6 +41,7 @@ __Be careful, a lot of my solutions aren't optimized because I didn't took time
 |Telephone Numbers| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/telephone_numbers.py) |
 |The Fall - Chapter 1| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/the_fall_1.py) |
 |The gift| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/the_gift.py)|
-|Dwarfs standing on the shoulders of giants| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/dwarfs_standing_on_the_shoulders_of_giants.py)
-
+|Dwarfs standing on the shoulders of giants| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/dwarfs_standing_on_the_shoulders_of_giants.py) |
+|Mayan Calculations| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/mayan_calculations.py) |
+|Scrabble| []() | [x](https://github.com/ARKAGEDON/CodingGame/blob/main/Python/Medium_Challenges/scrabble.py) |